(8x+3)(4x^2-19x-5)=0

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Solution for (8x+3)(4x^2-19x-5)=0 equation:


Simplifying
(8x + 3)(4x2 + -19x + -5) = 0

Reorder the terms:
(3 + 8x)(4x2 + -19x + -5) = 0

Reorder the terms:
(3 + 8x)(-5 + -19x + 4x2) = 0

Multiply (3 + 8x) * (-5 + -19x + 4x2)
(3(-5 + -19x + 4x2) + 8x * (-5 + -19x + 4x2)) = 0
((-5 * 3 + -19x * 3 + 4x2 * 3) + 8x * (-5 + -19x + 4x2)) = 0
((-15 + -57x + 12x2) + 8x * (-5 + -19x + 4x2)) = 0
(-15 + -57x + 12x2 + (-5 * 8x + -19x * 8x + 4x2 * 8x)) = 0
(-15 + -57x + 12x2 + (-40x + -152x2 + 32x3)) = 0

Reorder the terms:
(-15 + -57x + -40x + 12x2 + -152x2 + 32x3) = 0

Combine like terms: -57x + -40x = -97x
(-15 + -97x + 12x2 + -152x2 + 32x3) = 0

Combine like terms: 12x2 + -152x2 = -140x2
(-15 + -97x + -140x2 + 32x3) = 0

Solving
-15 + -97x + -140x2 + 32x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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